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2 years ago

How many moles are in 68.5 liters of oxygen gas at STP?

Chemistry

2 answers:

mr Goodwill [35]2 years ago

8 0

Answer:

3.0580 moles are in 68.5 liters of oxygen gas at STP

Explanation:

Let the number of moles of oxygen gas be n

Volume occupied by n moles of oxygen gas at STP = 68.5 L

At STP, 1 mol of gas occupies 22.4 L

Then 68.4 L of volume will be occupied by:

$\frac{1}{22.4} \times 68.5 L=3.0580 mol$

3.0580 moles are in 68.5 liters of oxygen gas at STP

givi [52]2 years ago

3 0

Since we know that one mole of any gas at STP is equal to 22.4 L we can multiply 135L by the following conversion: 1 mole/22.4L. When you set up the problem it looks like this…: (135L)x 1 mole/22.4L =6.03 moles of oxygen gas The liters cancel out and you are left with moles as your units.

So your answer is then 3.058

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Answer:

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In this question, the value of $Q$ (amount of heat supplied to the metal) and $m$ (mass of the metal sample) are the same for all four metals. To find $\Delta T$ (change in temperature,) rearrange the equation:

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In other words, the change in temperature of the sample, $\Delta T$ can be expressed as a fraction. Additionally, the specific heat of sample, $c$ , is in the denominator of that fraction. Hence, the value of the fraction would be the largest for sample with the smallest specific heat.

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Answer:

See explanation

Explanation:

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Answer:

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Explanation:

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