Answer:
The required probability is 0.55404.
Step-by-step explanation:
Consider the provided information.
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.
Average error for 7 pages booklet and 5 pages booklet series is:
λ = 0.2×7 + 0.3×5 = 2.9
According to Poisson distribution: 
Where 
is average number of events.
The probability of more than 2 typographical errors in the two booklets in total is:
Substitute the respective values in the above formula.
Hence, the required probability is 0.55404.
Answer:
if you just want 14% of 88
14% of 88 = 12.32, 0.14 * 88
if you want 14% of 88 + 88
114% of 88 = 100.32, 1.14 * 88
Step-by-step explanation:
2% of x = 0.02 * x
20% of x = 0.2 * x
200% of x = 2 * x
U need to show an example of the tiles in order for people to answer this
<span>2 and 3/4 punds of roast beef 2 3/4 = (4x2) + 3 /4= 11/4 roast beef
</span><span>1 and 7/8 pounds of turkey 1 7/8 = 15/8 </span>turkey
2 1/16 pounds of salami 2 1/16 33/16 <span>salami
</span><span>if you put 1/4 of pound of meat
</span>then 11/4 roast beef divided by 1/4 = 11/4 x4 = 11 sandwiches roast beef
15/8 turkey<span> divided 1/4 = 15/8 x 4 = 15/2 = 7 sandwishes
</span>
33/16 salami divided <span> 1/4 = 33/16 x 4 = 33/ 4 = 8 sandwiches</span>
3) adjacent
x = 180 - 34 = 146
4)adjacent
x = 90 - 74 = 16
6)supplementary
2x + 5 + 75 = 180
2x + 80 = 180
2x = 100
x = 50
