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2 years ago

A work out the value of 1^2+2^3+3^4 b work out the value of 4^2 x 2^4

Mathematics

2 answers:

bija089 [108]2 years ago

8 0

Answer:

Below in bold.

Step-by-step explanation:

Use order of operations: the exponents are calculated first, then multiplication, then addition.

a. 1^2+2^3+3^4

= 1 + 8 + 81

= 90.

b. 4^2 * 2^4

= 16 * 16

= 256.

IgorLugansk [536]2 years ago

7 0

Answer:

90 and 256.

Step-by-step explanation:

1^2 + 2^3 + 3^4

Solve for the powers or exponents first.

1 + 8 + 81

Add the numbers.

= 90

4^2 × 2^4

Solve for the powers or exponents first.

16 × 16

Multiply the numbers.

16^2

= 256

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Ok
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3 years ago

If I have a triangle with a leg of 4 and a leg of 3 what is the length of the hypotenuse

Dmitrij [34]

Answer:

Step-by-step explanation:

To solve for hypotenuse we use the Pythagorean theorem:

$a^2+b^2=c^2$

In this theorem:

c= hypotenuse

a = leg

b = leg

Substitute into theorem:

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(square root both sides)

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3 years ago

PLEASE ANSWER ASAPPPPPP! What is the quotient of 6 and -1/2.

const2013 [10]

Answer:

-12

Step-by-step explanation:

6 ÷ -1/2

Copy dot flip

6 * -2/1

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2 years ago

2. Find the distance between A (-1, 4) and B (1.-1)<br> 5.39<br> 5.19<br> 5.29<br> 5.09

Verizon [17]

<h3>Answer: A) 5.39</h3>

=====================================================

Explanation:

Apply the distance formula.

$d = \sqrt{ (x_1-x_2)^2+(y_1-y_2)^2}\\\\d = \sqrt{ (-1-1)^2+(4-(-1))^2}\\\\d = \sqrt{ (-1-1)^2+(4+1)^2}\\\\d = \sqrt{ (-2)^2+(5)^2}\\\\d = \sqrt{ 4+25}\\\\d = \sqrt{ 29}\\\\d \approx 5.38516\\\\d \approx 5.39\\\\$

You could also use the pythagorean theorem which is what the distance formula is based off of.

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2 years ago

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Alika [10]

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3 years ago