Mass of CaCl₂ = 0.732 g
<h3>Further explanation</h3>
The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.
Answer:
The advantage of this technique is that purified water as well as deposited metals can be re-used. It is necessary to use an inert electrode, such as platinum, because there is no metal present to conduct the electrons from the anode to the cathode.
Answer:
a, g, c
Explanation:
The conversion of the stable cyclopentane into Trans-1, 2dibromocyclopentane will require three step reactions.
The first is to convert the compound into a cyclopentene, through the addition of Bromine water under heat and photons (light). So option A is the first in the order. This will generate 1 bromocyclopentane through halogenation of the alkane. Secondly, a hot and strong base should be added like the NaOEt, EtOH to remove the added bromine and one atom of hydrogen from the resulting 1 bromocyclopentane in the previous reaction. This will yield cyclopentene, thus making the compound more electrophilic. So option g is required. Thirdly, bromine molecules will be added (C) to take up their places at the two electrophilic regions of the compound to produce Trans-1, 2dibromocyclopentane.
Answer:
there are 4 hydrogen so
A.the mass of Hydrogen in the reactant side of the equation above is 1×4=4 amu.
B.the mass of Hydrogen on the product side of the equation above =1×4=4 amu.
<u>Note</u><u>:</u><u> </u><u>mass</u><u> </u><u>of</u><u> </u><u>reactant</u><u> </u><u>=</u><u>mass</u><u> </u><u>of</u><u> </u><u>product</u><u>.</u>
From the stoichiometry of the reaction, 1.4 * 10^-3 g is produced.
<h3>What mass of water is produced?</h3>
The equation of the reaction is written as; CO2 + 2LiOH → Li2CO3 + H2O. This can help us to apply the principle of stoichiometry here.
Thus;
Number of moles of CO2 = 0.00345 g/44 g/mol = 7.8 * 10^-5 moles
If 1 mole of CO2 produced 1 mole of water
7.8 * 10^-5 moles of CO2 produced 7.8 * 10^-5 moles of water
Mass of water produced = 7.8 * 10^-5 moles * 18 g/mol = 1.4 * 10^-3 g
Learn ore about stoichiometry:brainly.com/question/9743981
#SPJ1