2 years ago

Solve the equation algebraically. x^2-7x-1/7=0

Mathematics

1 answer:

valentina_108 [34]2 years ago

7 0

Answer:

$x1=\frac{49+\sqrt{2429}}{14} \\x2=\frac{49-\sqrt{2429}}{14} \\$

Step-by-step explanation:

$x^2-7x-\frac{1}{7} =0\\7x^2-49x-1=0\\D=b^2-4ac=(-49)^2-4*7*(-1)=2429\\x1=\frac{49+\sqrt{2429} }{14} \\x2=\frac{49-\sqrt{2429} }{14} \\$

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