A recipe requires 1/3 cup of milk for each 1/4 cup of water. How many cups of water

Fourteen more than a number is eighteen.

AVprozaik [17]

Answer: 4

Step-by-step explanation:

18-14=4

3 0

3 years ago

In the exponential growth function y = 235(1.15)^x, what is the

sweet-ann [11.9K]

Answer: Growth factor will be 0.15 and percent increase will be 15%.

Step-by-step explanation:

Since we have given that

the exponential growth function

$y=235(1.15)^x$

1) We need to find the growth factor :

As we know the formula for "Compound Interest ":

$A=P(1+\frac{r}{100})^x$

If we compare the formula with our given equation, we get

$1+\frac{r}{100}=1.15\\\\\frac{r}{100}=1.15-1\\\\\frac{r}{100}=0.15\\\\r=0.15\times 100\\\\r=15$

So, the growth factor is at the rate of 0.15.

2) Percent increase will be

$0.15=\frac{15}{100}\times 100\\\\=15\%$

Hence, growth factor will be 0.15 and percent increase will be 15%.

3 0

2 years ago

.0417 DIVIDED 100 PLZ HELP (⊙_⊙)

nikklg [1K]

Answer: 0.000417

Hope this helps can u give me brainliest

Step-by-step explanation:

7 0

2 years ago

What is the interquartile range of 45,60,40,90,60,50,75,120,90

puteri [66]

IQR = 40

1) Put the numbers in order: 40, 45, 50, 60, 60, 75, 90, 90, 120
2) Find the median: Median is 60 (the 2nd one)
3) Place parentheses around the numbers above and below the median. For easy identification of Q1 and Q3. (40, 45, 50, 60,) 60, (75, 90, 90, 120)
4) Find the Q1 and Q3. Q1 = median of the lower half of the data; Q3 = median of the higher half of the data. Q1 and Q3 have even sets so its median cannot be defined.
5) Had both sets contain odd sets, the median of Q1 is subtracted from the median of Q3 to get the IQR.

We can then use the Alternative definition of IQR.
IQR is the difference between the largest and smallest values in the middle 50% of a set data.

40, 45, 50, 60, 60, 75, 90, 90, 120

Middle 50% is 50, 60, 60, 75, 90; IQR = Largest value - smallest value;

IQR = 90 - 50 = 40

5 0

2 years ago

2. The quality assurance department inspects its production line. The product either fails or passes the inspection. Past experi

Oksana_A [137]

Answer:

(a) $E(X) = 950$

(b) $COV = 0.007255$

(c) $P(X > 980) = 0.00001\\\\$

Step-by-step explanation:

The given problem can be solved using binomial distribution since the product either fails or passes, the probability of failure or success is fixed and there are n repeated trials.

probability of failure = q = 0.05

probability of success = p = 1 - 0.05 = 0.95

number of trials = n = 1000

(a) What is the expected number of non-defective units?

The expected number of non-defective units is given by

$E(X) = n \times p \\\\E(X) = 1000 \times 0.95 \\\\E(X) = 950$

(b) what is the COV of the number of non-defective units?

The coefficient of variance is given by

$COV = \frac{\sigma}{E(X)}$

Where the standard deviation is given by

$\sigma = \sqrt{n \times p\times q} \\\\\sigma = \sqrt{1000 \times 0.95\times 0.05} \\\\\sigma = 6.892$

So the coefficient of variance is

$COV = \frac{6.892}{950}$

$COV = 0.007255$

(c) What is the probability of having more than 980 non-defective units?

We can use the Normal distribution as an approximation to the Binomial distribution since n is quite large and so is p.

$P(X > 980) = 1 - P(X < 980)\\\\P(X > 980) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\$

We need to consider the continuity correction factor whenever we use continuous probability distribution (Normal distribution) to approximate discrete probability distribution (Binomial distribution).

$P(X > 980) = 1 - P(Z < \frac{979.5 - 950}{6.892} )\\\\P(X > 980) = 1 - P(Z < \frac{29.5}{6.892} )\\\\P(X > 980) = 1 - P(Z < 4.28)\\\\$

The z-score corresponding to 4.28 is 0.99999

$P(X > 980) = 1 - 0.99999\\\\P(X > 980) = 0.00001\\\\$

So it means that it is very unlikely that there will be more than 980 non-defective units.

8 0

2 years ago