Answer:
a) 3.6
b) 1.897
c)0.0273
d) 0.9727
Step-by-step explanation:
Rabies has a rare occurrence and we can assume that events are independent. So, X the count of rabies cases reported in a given week is a Poisson random variable with μ=3.6.
a)
The mean of a Poisson random variable X is μ.
mean=E(X)=μ=3.6.
b)
The standard deviation of a Poisson random variable X is √μ.
standard deviation=S.D(X)=√μ=√3.6=1.897.
c)
The probability for Poisson random variable X can be calculated as
P(X=x)=(e^-μ)(μ^x)/x!
where x=0,1,2,3,...
So,
P(no case of rabies)=P(X=0)=e^-3.6(3.6^0)/0!
P(no case of rabies)=P(X=0)=0.0273.
d)
P(at least one case of rabies)=P(X≥1)=1-P(X<1)=1-P(X=0)
P(at least one case of rabies)=1-0.0273=0.9727
Answer:
Positive
Step-by-step explanation:
-465+465
= 465-465
=0
Zero is positive.
I've attached a plot of one such cross-section (orange) over the region in the x-y plane (blue), including the bounding curves (red). (I've set
for this example.)
The length of each cross section (the side lying in the base) has length determined by the horizontal distance
between the y-axis
and the curve
. In terms of
, this distance is
. The height of each cross section is twice the value of
, so the area of each rectangular cross section should be
.
This means the volume would be given by the integral
1-3
2-6
3-9 This is an example of porportional.
1-4
2-3
3-9 There is no pattern so thin is Non-Porportional.