(−8* y^2−9*y)+(8*y^3+9*y^2−2*y)
first, remove extraneous parentheses (or distribute if negative)
=−8* y^2−9*y+8*y^3+9*y^2−2*y
then group terms in decreasing degree of y (variable)
=+8*y^3 −8* y^2+9*y^2 −9*y−2*y
simply expression by adding/subtracting similar terms
=+8*y^3 +y^2 −11*y
to give the final answer.
Answer:
x=12
Step-by-step explanation:
2x-4=20
2x=24
x=12
How to find rapidly the coordinates of Q:
since Q is the center of gravity of the triangle ABC, so we have the following vector relationship
vecQA +vecQB +vecQC =<span>vec0
</span><span>vecQA=(x-3, y+2)
</span><span>vecQB=(x-1, y+5)
</span><span>vecQC=(x-7, y+5)
</span><span>vec0=(0, 0)
</span>
so, vecQA +vecQB +vecQC =<span>vec0 is equivalent to
</span>x-3 +x-1+x-7 =0, and y+2+y+5+<span>y+5=0 so 3x-11=0 implies x=11/3
</span><span>and 3y+12=0 implies y=-12/3
finally the </span><span>the coordinates of point Q is (11/3, -4)</span><span>
</span>
Answer:
The standard form of such an equation is Ax + By + C = 0 or Ax + By = C. When you rearrange this equation to get y by itself on the left side, it takes the form y = mx +b. This is called slope intercept form because m is equal to the slope of the line, and b is the value of y when x = 0, which makes it the y-intercept.
Step-by-step explanation:
