The magnitude of the electrical force between a pair of charged particles is 4 Times as much when the particles are moved half as far apart.
This can be easily understood by Columb's law,
which state's that the amount of electrical force experienced by two charged particles is inversely proportional to the square of the distance between them.
∴
Now, we know the new distance is half the original distance,
The electrical force of attraction or electrostatic force of attraction between two charged particles refers to the amount of attractive or repulsive force that exists between the two charges. This can be calculated by Columb's Law.
A charged particle in physics is a particle that has an electric charge. It might be an ion, such as a molecule or atom having an excess or shortage of electrons in comparison to protons. The same charge is thought to be shared by an electron, a proton, or another primary particle.
Learn more about electrical force here
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Complete Question
The distance between the objective and eyepiece lenses in a microscope is 19 cm . The objective lens has a focal length of 5.5 mm .
What eyepiece focal length will give the microscope an overall angular magnification of 300?
Answer:
The eyepiece focal length is
Explanation:
From the question we are told that
The focal length is
This negative sign shows the the microscope is diverging light
The angular magnification is
The distance between the objective and the eyepieces lenses is
Generally the magnification is mathematically represented as
Where is the eyepiece focal length of the microscope
Now making the subject of the formula
substituting values
To solve this problem we will use the relationship given between the centripetal Force and the Force caused by the weight, with respect to the horizontal and vertical components of the total tension given.
The tension in the vertical plane will be equivalent to the centripetal force therefore
Here,
m = mass
v = Velocity
r = Radius
The tension in the horizontal plane will be subject to the action of the weight, therefore
Matching both expressions with respect to the tension we will have to
Then we have that,
Rearranging to find the velocity we have that
The value of the angle is 14.5°, the acceleration (g) is 9.8m/s^2 and the radius is
Replacing we have that
Therefore the speed of each seat is 4.492m/s
Answer: the first one is speed
the second one is acceleration
the last is velocity
Explanation:
i got you
Gravity on the surface = 4 m/s^2
Now, the acceleration due to centripetal motion, a = v^2/R
Where,
v= 10^3 m/s, R = 10^6 m
Then,
a = (10^3)^2/(10^6) = 1 m^2/s
The net gravitational acceleration = 4-1 = 3 m/s^2
The reading on the spring scale = ma = 40*3 = 120 N