I think it means which graph is the best at representing the data or data set.
For example if you were to graph the population of an animal you would use a line graph to represent the data
If you were determining how much percentage you would get a job you would use a pie graph. Etc
Answer:
lies between 0 and 1.
Step-by-step explanation:
We must have in mind that given average weight of a newborn panda is a non-integer rational number, such that lies between two integer rational number. In other words, this number must satisfy the following condition:
,
Which is now developed mathematically to deduce a useful expression to find integers:
1) Given
2) Modulative property
3) Existence of Multiplicative inverse/Definition of division.
4) Commutative, Associative and Distributive properties.
5) Compatibility with Multiplication/Existence of Multiplicative Inverse/Modulative Property/Result.
If we know that and , the following inequation is formed:
It is quite evident to conclude that lies between 0 and 1.
Recursive
formula is one way of solving an arithmetic sequence. It contains the initial
term of a sequence and the implementing rule that serve as a pattern in finding
the next terms. In the
problem given, the 6th term is provided, therefore we can solve for the initial
term in reverse. To make use of it, instead of multiplying 1.025, we should divide it after
deducting 50 (which supposedly is added).
<span>
Therefore, we perform the given formula: A (n) = <span>1.025(an-1) +
50
</span></span>a(5) =1.025 (235.62) + 50 = 291.51
a(4) = 1.025 (181.09) + 50 = 235.62
a(3) = 1.025 (127.89) + 50 = 181.09
a(2) = 1.025 (75.99) + 50 = 127.89
a(1) = 1.025 (25.36) + 50 = 75.99
a(n) = 25.36
The terms before a(6) are indicated above, since a(6) is already given.
So, the correct answer is <span>
A. $25.36, $75.99.</span>
Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one