Probability that a student will play both is 7/30
Step-by-step explanation:
Total students = 30
No. of students who play basketball = 18
Probability that a student will play basketball = 18/30
= 3/5
No. of students who play baseball = 9
Probability that a student will play baseball = 9/30
= 3/10
No. of students who play neither sport = 10
Probability that a student will play neither sport = 10/30
= 1/3
To find :
Probability that a student will play both = p(student will play both)
No.of students who play sport = 30 - 10
= 20
Out of 20 students 18 play basketball and 9 play baseball.
So, some students play both the sports.
No. of students who play both sports = 18 + 9 - 20
= 7
p(student will play both) = 7/30
Probability that a student will play both is 7/30
Since you'd didn't specify what place value I'm assuming it's the whole number so the answer is: 80,000,000
Sat + Sun = 52
Sun = Sat + 8
Sat + Sat + 8 = 52
2Sat + 8 = 52
2Sat + 8-8 = 52-8
2Sat = 44
2Sat/2 = 44/2
Sat = 22
Sun = 22 + 8
Sun = 30
Check
Sat + Sun = 52
22 + 30 = 52
52 = 52
Answer:
25
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Step-by-step explanation:
5y + x - y; use x = 1, and y = 6
You plug the numbers in.
5(6) + 1 - 6
30+1-6
25