If an object is dropped from a height of 55 feet, the function d = -16^2 + 55 gives the height of the object after t seconds. Gr
aph this function. Approximately how long does it take the object to reach the ground (d=0)
2 answers:
Answer:
t is approximately 1.854049622 seconds
Step-by-step explanation:
d = -16 t^2 + 55
Let d = 0
0 = -16 t^2 + 55
Subtract 55 from each side
-55 = -16 t^2
Divide by -16 on each side
-55/-16 = -16 /-16t^2
55/16 = t^2
Take the square root of each side
sqrt(55/16) = sqrt(t^2)
We only take the positive square root because time must be positive
sqrt(55/16) = t
t is approximately 1.854049622 seconds
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I hope this helps!
Answer:
A. x²/y³
Step-by-step explanation:
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