Answer:
27.98g/mol
Explanation:
Using ideal gas law equation;
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
T = temperature (K)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
According to the information given:
V = 2.5L
P = 1.4 atm
T = 282K
n = ?
Using PV = nRT
n = PV/RT
n = 1.4 × 2.5/0.0821 × 282
n = 3.5/23.1522
n = 0.151mol
Using the formula to calculate molar mass of the elemental gas:
mole = mass/molar mass
Molar mass = mass/mole
Molar mass = 4.23g ÷ 0.151mol
Molar mass = 27.98g/mol
Answer:
3–heptene or Hept–3–ene.
Explanation:
To name the compound given in the question above, we must determine the following:
1. Identify the functional group of the compound.
2. Locate the longest continuous carbon chain. This gives the parent name of the compound.
3. Identify the substituent group attached to the compound.
4. Locate the position of the double bond (i.e the functional group) by giving it the lowest possible count.
5. Combine the above to obtain the name of the compound.
Now, we shall obtain the name of the compound as follow:
1. The compound contains double bond. Hence the compound is an alkene.
2. The longest continuous carbon chain is 7 i.e heptene.
3. No substituent group is attached to the compound.
4. The double bond is located at carbon 3 since counting from the right gives the lowest count for the double bond.
5. The name of the compound is:
3–heptene or Hept–3–ene
Answer: 58.305torr
Explanation:
We shall solve this using Raoult law.
Mathematical expression is;
Ptotal=XaPa + XbPb
Where Xa, Xb and Pa Pb are the mole fraction and vapor pressure of each component. we shall now solve this by steps
STEP1: Find the mole of benzene and Toluene;
Mole= mass÷molar mass
For toluene:
Mass= 398g
Molar mass= 92.1g/mol
Mole= 398÷92.1 =4.32mol
For benzene:
Mass=734g
Molar mass= 78.1g/mol
Mole= 734÷78.1 = 9.398mol
STEP2: Find the mole fraction of each component:
Let Xb be mole fraction for benzene
Let Xt be mole fraction for toluene.
Therefore; nB+nT = X
nB and nT are the mole of component B and T
X= 4.32+9.398= 13.718
Mole fraction for Toluene;
Xt= nT÷X
4.32÷13.718= 0.315
Mole fraction for benzene;
Xb= nB÷X
9.398÷13.718= 0.685
STEP3: Find the total total pressure;
We will use Rauolt law.
Ptotal= XbPb + XtPt
Pt = 22torr
Pb = 75torr
Therefore Ptotal is;
(0.315×22) + (0.685×75) = 6.93+51.375= 58.305
Therefore the total pressure is 58.305torr
Answer:
N
Explanation:
Electronegativity increases as you move from left to right across a period, and decreases as you move down the groups.
