Answer: C. 30.47
Step-by-step explanation:
The mean of discrete random variable i.e. the expected value of X is given by :-
Now by using the given table, the expected value of X is given by :-
Hence, the mean of discrete random variable= 30.47
answer:
x=1/3
x=11/3
STEP 1:
Rearrange this Absolute Value Equation
Absolute value equalitiy entered
-3|x-2|+9 = 4
Another term is moved / added to the right hand side.
To make the absolute value term positive, both sides are multiplied by (-1).
3|x-2| = 5
STEP 2:
Clear the Absolute Value Bars
Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.
The Absolute Value term is 3|x-2|
For the Negative case we'll use -3(x-2)
For the Positive case we'll use 3(x-2)
STEP 3:
Solve the Negative Case
-3(x-2) = 5
Multiply
-3x+6 = 5
Rearrange and Add up
-3x = -1
Divide both sides by 3
-x = -(1/3)
Multiply both sides by(-1)
x = (1/3)
Which is the solution for the Negative Case
STEP 4:
Solve the Positive Case
3(x-2) = 5
Multiply
3x-6 = 5
Rearrange and Add up
3x = 11
Divide both sides by 3
x = (11/3)
Which is the solution for the Positive Case
giving us x=1/3 or x=11/3
allso if u can i need help with a thing so plese help, i would aprestiate it
brainly.com/question/25340824
Here is the set up:
Side 1 is 4x.
Side 2 is 5x + 3
Side 3 is 5x + 1
The perimeter is 102.
Perimeter = side 1 + side 2 + side 3
102 = 4x + 5x + 3 + 5x + 1
102 = 14x + 4
Take it from here.
You can either use the inverse function theorem or compute the general derivative using implicit differentiation. The first method is slightly faster.
The IFT goes like this: if f(x) is invertible and f(a) = b, then finv(b) = a (where "finv" means "inverse of f").
By definition of inverse functions, we have
f(finv(x)) = finv(f(x)) = x
Differentiating both sides of the second equality with respect to x using the chain rule gives
finv'(f(x)) * f'(x) = 1
When x = a, we get
finv'(b) * f'(a) = 1
or
finv'(b) = 1/f'(a)
Now let f(x) = sin(x), which is invertible over the interval -π/2 ≤ x ≤ π/2. In the interval, we have sin(x) = √3/2 when x = π/3. We also have f'(x) = cos(x).
So we take a = π/3 and b = √3/2. Then
arcsin'(√3/2) = 1/cos(π/3) = 1/(1/2) = 2
30
2x12=24
0.5x12=6
24+6=30
hope that helps
