2 years ago

Which is an example of an object with a momentum of zero?(1 point)

Physics

2 answers:

QveST [7]2 years ago

8 0

B will be correct hopefully this helps

kirza4 [7]2 years ago

4 0

Answer:

Explanation:

A) gravity

B) force of the diver

C) air blowing out from the hockey table

D) has no know outside Force acting on it

You might be interested in

Einstein and lorentz, being avid tennis players, play a fast-paced game on a court where they stand 19.0 m from each other. bein

Dvinal [7]

So sometimes when you actually do you work it’s happens and you get answers idk about that

7 0

2 years ago

A child is prescribed a drug X; the recommended manufacturer’s dose is 2.50 mg/m2. The body surface area (BSA) of the child is 1

guapka [62]

Answer: 3.75 mg

Explanation:

We need a dose of 2.50 mg per square meter of BSA, and we also know that the BSA of the child is 1.50 m^2, then if the dosage should be 2.50mg for one m^2, for 1,5 m^2 we should administrate an amount of:

D = 1.5 m^2*(2.50mg/m^2) = 1.5*2.5 mg = 3.75 mg

3 0

2 years ago

Need help with #7 and 8 ASAP

NeTakaya

Answer:

a) 0.278 b) 22.2

Explanation:

6 0

2 years ago

An object with a mass of 1.5kg changes its velocity from +15m/s to +22 during a time interval of 3.5 seconds. What Impulse was d

Shalnov [3]

B: 11 N.s is the answer

7 0

2 years ago

3) A driver in a 1000-kg car traveling at 24 m/s slams on the brakes and skids to a stop. If the coefticient of friction between

Natali5045456 [20]

Answer:

A) 37 m

Explanation:

The car is moving of uniformly accelerated motion, so the distance it covers can be calculated by using the following SUVAT equation:

$v^2 -u^2 = 2ad$ (1)

where

v = 0 m/s is the final velocity of the car

u = 24 m/s is the initial velocity

a is the acceleration

d is the length of the skid

We need to find the acceleration first. We know that the force responsible for the (de)celeration is the force of friction, so:

$F=ma=-\mu mg$

where

m = 1000 kg is the mass of the car

$\mu = 0.80$ is the coefficient of friction

a is the deceleration of the car

g = 9.8 m/s^2 is the acceleration due to gravity

The negative sign is due to the fact that the force of friction is against the motion of the car, so the sign of the acceleration will be negative because the car is slowing down. From this equation, we find:

$a=-\mu g$

And we can substitute it into eq.(1) to find d:

$v^2 -u^2 = 2(\-mu g) d\\d= \frac{v^2-u^2}{-2 \mu g}=\frac{0-(24 m/s)^2}{-2(0.80)(9.8 m/s^2)}=36.7 m \sim 37 m$

7 0

2 years ago