Applying 1st law of thermodynamics:
Q = Delta U + WB
WB is the workdone by the system
<span>WB = 346 J </span>
As,
<span>Delta U = ( m ) ( CV ) ( T2 - T1 ) </span>
<span>CV = ( Delta U ) / ( m ) ( T2 - T1 )
</span>Putting the values in equation:
<span>CV = ( 8485 J ) / ( 80.0 g ) ( 225 C - 25 C ) </span>
<span>CV = 0.5303 J / g - C degree </span>
Now putting in original equation:
<span>Q = Delta U + WB </span>
<span>Q = ( 8485 ) + ( 346 ) = 8831 J
8831J is the specific heat of the gas</span>
Answer:
I think is d.
Explanation:
particles that make up the nucleus are balanced. An atom is unstable (radioactive) if these forces are unbalanced; if the nucleus has an excess of internal energy. the Instability of an atom's nucleus may result from an excess of either neutrons or protons.
I'm not sure, but hope it helps.
13. Nt
14. St
15. St
16. At
17. Nt
