Answer:
the angular acceleration is 9.7 rad/
Explanation:
given information:
mass of thin rod, m = 3.2 kg
the length of the rod, L = 1.2
angle, θ = 38
to find the acceleration of the rod, we can use the torque's formula as below,
τ = Iα
where
τ = torque
I = inertia
σ = acceleration
moment inertia of this rod, I
I =
τ = F d, d = cosθ
τ = m g cosθ
now we can substitute the both equation,
τ = Iα
α = τ/I
= (m g cosθ)/()
= 3gcosθ/2L
= 3 (9.8)cos 38°/(2 x 1.2)
= 9.7 rad/
By V=IR
A: 24=I*20
I = 1.2A
B: 220 = I*250
I = 0.88A
C: 6= I*3
I = 2 A
C,A,B
Answer:
1275J
Explanation:
Given parameters:
Force on box = 85N
Distance moved = 15m
Unknown:
Work done = ?
Solution:
Work done is the amount of force applied on a body to move it through a specific distance.
Work done = Force x distance
Now insert the parameters and solve;
Work done = 85 x 15 = 1275J
Answer:
Explanation:
Speed = distance / time
Velocity = displacement / time
So ,
Speed = 50 km / 0.5 hr = 100 km/h
Velocity = 40 km / 0.5hr = 80 km/h
You don't need to worry about the 10 year bit with this question. Just grab a calculator and divide 100/2, then the answer to that (50) by 2 etc and keep dividing by 2 until you get down to 6.25.
The answer ends up being 4 half lives :)
If you don't understand what a half life is please let me know :)