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2 years ago

What is the volume of a right circular cylinder with a base diameter of 18yd. And a height of 3yd.

Mathematics

1 answer:

saveliy_v [14]2 years ago

8 0

Answer:

$Volume=254$ to the nearest cubic yard.

Step-by-step explanation:

The volume of a right circular cylinder can be calculated using the formula;

$Volume=\pi r^2h$ .

The diameter of the base is given to us. We divide it into two to obtain the radius.

$r=\frac{18}{2}=9yd$ and also the height of the cylinder is $h=3yd$ .

We substitute these values into the formula to obtain;

$Volume=9^2\times 3\pi yd^3$

$Volume=243\pi yd^3$

$Volume=763.4yd^3$

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Step-by-step explanation:

vertical angles are angles that are across from each other

so they can either be obtuse or acute

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2 years ago

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What is the difference between linear pair supplementary angle and straight angle?

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2 years ago

What is the value of x?

guajiro [1.7K]

Answer:

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Step-by-step explanation:

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4 0

2 years ago

<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20x%20%7B%7D%5E%7B2%7D%20%20%2B%2012x%20%2B%2036" id="TexFormula1" title="f(x)

Mars2501 [29]

Answer:

Step-by-step explanation:

We are given the function:

$\displaystyle f(x) = x^2 + 12x + 36$

And we want to determine the value of:

$\displaystyle f^{-1}(225)$

Let this value equal <em>a</em>. In other words:

$\displaystyle f^{-1}(225) = a$

Then by the definition of inverse functions:

$\displaystyle \text{If } f^{-1}(225) = a\text{, then } f(a) = 225$

Hence:

$\displaystyle f(a) =225 = (a)^2 + 12(a) + 36$

Solve for <em>a: </em>

$\displaystyle \begin{aligned} 225 &= a^2 + 12a + 36 \\ \\ a^2 + 12a -189 &= 0 \\ \\ (a + 21)(a-9) &= 0\end{aligned}$

By the Zero Product Property:

$\displaystyle a + 21 = 0 \text{ or } a - 9 = 0$

Hence:

$\displaystyle a = -21 \text{ or } a = 9$

Thus, f(9) = 225. Consequently, f⁻¹(225) = 9.

In conclusion, our answer is B.

3 0

2 years ago