Only bacteria can reproduce outside a host and bacteria are not dependent on a host
Answer:
C. Under the age of 20
Explanation:
Look at the graph and find what letter the male's bar is larger than the female's. You can see that it's letter B. Then, look at the legend and find what ages lay under letter B. It is C., under the age of 20.
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Admitting that the "a" is a capital A for normal pigmentation and "d" is a capital D for dimpled chin, meaning that these are the dominant traits, the fraction expected to be albino with a non-dimpled chin is of 1/16.
When two heterozygous are crossed and two characteristics are being analysed, the offspring quantity that will possess the two recessive traits can be represented by 1/16. This is easily confirmed when a Punnett square is made. Considering that both parents were heterozygous, on both sides of the crossing in the Punnett square, you would have the following alleles' combination: AD, Ad, aD, and ad. The offspring that would be homozygous recessive (aadd) would correspond to only 1/16.
I think the correct answer is C. Hope this helps.
