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2 years ago

13

Of the original 56 signers of the declaration of independence four of them are present in North Carolina if you selected one sig

n randomly how likely is it that he represent in North Carolina

1 answer:

kari74 [83]2 years ago

8 0

The chance of you selecting one randomly is 4/56, which simplifies to 1/14.

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The area of a tabletop is 48 square feet. the length is 3 times the width.if the dimensions are whole numbers, what is the width

posledela

(4 feet wide), 12 feet in length. 4*3=12 4*12=48

7 0

2 years ago

PLS HELP EMERGENCY what is 4/25 times 10. PLEASE ANSWER AS A FRACTION IN SIMPLEST FORM

Nookie1986 [14]

The answer is 8/5.

4/5 x 10 = 1 3/5

= 8/5.

4 0

2 years ago

93,871 round to the nearest hundreds

VMariaS [17]

Answer:

93,900

Step-by-step explanation:

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2 years ago

Read 2 more answers

Triangles and algebra

Elanso [62]

Hello from MrBillDoesMath!

Answer:

x = 10

Discussion:

A plane triangle contains 180 degrees. Adding the angles in the triangle shown in #8 gives

(4x + 7) + (3x + 13) + 90 = 180

Note the "right angle" shown in the triangle has been replaced by its 90 degree equivalent in the above equation.

Combining like terms gives

( 4x + 3x) + (7 + 13) + 90 = 180

7x + 20 + 90 = 180 => (subtract 90 from each side)

7x + 20 + 90 - 90 = 180 - 90 = 90 =>

7x +20 = 90 => (subtract 20 from each side)

7x + 20 -20 = 90 -20 =>

7x = 70 =>

x 70/7 =10.

Thank you,

MrB

3 0

2 years ago

A data set includes data from student evaluations of courses. The summary statistics are nequals83, x overbarequals3.32, sequa

Andrews [41]

Answer:

Hypothesis

Null hypothesis: $\mu =3.50$

Alternative hypothesis: $\mu \neq 3.50$

Statistic

$t=\frac{3.32-3.50}{\frac{0.56}{\sqrt{83}}}=-2.928$

P value

The degrees of freedom are given by:

$df=n-1=83-1=82$

And the p value would be given by:

$p_v =2*P(t_{(82)}$

Conclusion

Since the p value is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 3.5

Step-by-step explanation:

Information given

$\bar X=3.32$ represent the sample mean

$s=0.56$ represent the sample deviation

$n=83$ sample size

$\mu_o =3.5$ represent the value to test

t would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to verify if the true mean is equal to 3.5, the system of hypothesis are:

Null hypothesis: $\mu =3.50$

Alternative hypothesis: $\mu \neq 3.50$

Statistic

The statistic would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing we got:

$t=\frac{3.32-3.50}{\frac{0.56}{\sqrt{83}}}=-2.928$

P value

The degrees of freedom are given by:

$df=n-1=83-1=82$

And the p value would be given by:

$p_v =2*P(t_{(82)}$

Conclusion

Since the p value is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 3.5

8 0

2 years ago