Can someone helpp???

Mathematics

1 answer:

neonofarm [45]2 years ago

6 0

AD and FC are perpendicular so they make a 90 degree angles. Angle BDC is equal to angle FDE so its 25. then u take 90 and subtract 25 to find the anser your looking for... so its 65

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An airplane is flying overhead at a constant elevation of 405 ft. A person is viewing the plane from a position 3040 ft from the

Gnoma [55]

Answer:

δL/δt = 634,38 ft/s

Step-by-step explanation:

A right triangle is shaped by ( y = distance between aircraft and ground which is constant and equal to 405 f ) a person who is at ground level 3040 f away from the tower distance x = 3040 f and the line between the aircraft and the person. Then we can use Pythagoras theorem and write

L ( distance between aircraft and person )

L² = x² + y² or L² = x² + (405)²

Taken partial derivatives with respect to t we get:

2*L*δL/δt = 2*x*δx/t + 0

Then L*δL/δt = x*δx/dt

At the moment of the aircraft passing over the tower

x = 3040 ft δx/δt = 640 ft/s and L = √ ( 3040)² + (405)²

So L = √9241600 + 164025 L = √9405625 L ≈3066,9 ft

Then:

δL/δt = 3040*640/ 3066,9 units [ ft * ft/s / ft ] ft/s

δL/δt = 634,38 ft/s

5 0