Since its a six sided die the probability for rolling a single number ( like six or four) is always going to be 1/6.
and since the dice has the numbers 1, 2, 3, 4, 5 and 6 on it the probability for the even and the odd numbers are the same the even being 2, 4, 6 and odd being 1, 3, 5. the probability is 3/6 or simplified 1/2.
Answer:
14.6
Explanation:
It's pretty simple if you use a calculator, have a nice day and good luck with your work! <3
Start by factoring an x term out of the equation:
x(x-11)=0
Now, you can set each term equal to zero and solve for x:
x=0
x-11=0
x=11
x={0, 11}
Hope this helps!!
Answer:
3.00x10^8
Step-by-step explanation:
So you want to make sure the number before the x10^ is beween 10 and 0 not including 10 and 0. So 1.00-9.99.
Move the demcil place up in 300,000,000 till your first number is between 1 and 9.99.
Then count how many places you moved it up, in this case 8
Add the amount of times you moved up to the x10^(in this space).
you answer is now 3.00 plus the x10^8
3.00x10^8
Answer:
50.33 mi.
Step-by-step explanation:
<u>GIVEN :-</u>
Coordinates of :-
- Home = (0 , 0)
- School = (4 , 3)
- Pizza place = (-8 , 2)
- Movie Theater = (-4 , -6)
- Park = (7 , -5)
<u>TO FIND :-</u>
- Total distance travelled on Friday & Saturday.
<u>GENERAL FORMULAE TO BE USED IN THIS QUESTION :-</u>
Lets say there are two points A & B on a cartesian plane whose coordinates are (x₁ , y₁) & (x₂ , y₂).
Distance between A & B =
<u>SOLUTION :-</u>
According to question ,
On Friday , you -
- leave school and go to pizza palace. Distance travelled from school to pizza palace = ≈ 12.04 mi.
- go to movie theater after pizza palace. Distance travelled from pizza palace to movie theater = ≈ 8.94 mi.
- come back to your home after the movies. Distance travelled from theater to home = ≈ 7.21 mi.
⇒ <em>On Friday , total distance travelled = 12.04 + 8.94 + 7.21 = 28.19 mi.</em>
On Saturday , you -
- go to park from your home. Distance travelled from home to park = ≈ 8.6 mi.
- go to school after going to park. Distance travelled from park to school = ≈ 8.54 mi.
- go to home after playing basketball in school. Distance travelled from school to home = = 5 mi.
⇒ <em>On Saturday , total distance travelled = 8.6 + 8.54 + 5 = 22.14 mi.</em>
∴ Total distance travelled on Friday & Saturday = 28.19 + 22.14 = 50.33 mi.