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ludmilkaskok [199]

2 years ago

7

Solve the equation the square of 2x + 1 equals the square of x + 4

1 answer:

gavmur [86]2 years ago

8 0

I am sorry this is where I can get too.

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Salma received a $90 gift card for a coffee store. She used it in buying some coffee that cost $8.33 per pound. After buying the

hichkok12 [17]

Answer:

4 Pounds.

Step-by-step explanation:

90 - 56.68 = 33.32

33.32 / 8.33 = 4

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Pentagon ABCDE Is the image of pentagon ABCDE under a dilation with a scale factor of 3/2 What is the length of segment overline

Ugo [173]

Answer:

4

Step-by-step explanation:

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2 years ago

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denpristay [2]

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2 years ago

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Please. Answer Fast! Use composition to determine if G(x) or H(x) is the inverse of F(x) for the

s344n2d4d5 [400]

Answer:

A. H(x) is an inverse of F(x)

Step-by-step explanation:

The given functions are:

$F(x)=\sqrt{x-2}$

$G(x)=(x-2)^2$

$H(x)=x^2+2$

We compose F(x) and G(x) to get:

$(F\circ G)(x)=F(G(x))$

$(F\circ G)(x)=F((x-2)^2)$

$(F\circ G)(x)=\sqrt{(x-2)^2-2}$

$(F\circ G)(x)=\sqrt{x^2-4x+4-2}$

$(F\circ G)(x)=\sqrt{x^2-4x+2}$

$(F\circ G)(x)\ne x$

Hence G(x) is not an inverse of F(x).

We now compose H(x) and G(x).

$(F\circ H)(x)=F(H(x))$

$(F\circ H)(x)=F(x^2+2)$

$(F\circ H)(x)=\sqrt{x^2+2-2}$

We simplify to get:

$(F\circ H)(x)=\sqrt{x^2}$

$(F\circ H)(x)=x$

Since $(F\circ H)(x)=x$ , H(x) is an inverse of F(x)

3 0

2 years ago