Uh so I'm no master at this subject, but all stuffs accelerate at 9.8 m/s squared. So you multiply the 9.8 and the 0.20 it's given for reasons unknown other than that's what I see in my notes... and that gives you 1.96 m/s squared.
As for B, I have no idea. I think you may multiply the 1.96 by 4. Tell me your thoughts and maybe we can work it out together
Average speed =
(distance covered during some period of time)
divided by
(length of time to cover that distance).
Answer:
0.958 m
Explanation:
So the total mass of the system is
M = 1.93 + 2.95 + 2.41 + 3.99 = 11.28 kg
let y be the distance from the center of mass to the origin. With the reference to the origin then we have the following equation
So the center of mass is 0.958 m from the origin
Answer:
a.3.84m
b.-106.67m/s
c.947.3m/s^2
d.70.17 rad
e.2.5Hz
d.0.4secs
Explanation:
Given x=(7.8)cos[5πrad/s)t+π/3)]
a.Displacement at t=4.4
7.8cos(5π*4.4+π\3)=3.84m
b.velocity
V= dx/dr=-5π(7.8)sin(5πrad/s)t+π\3
at t=4.4
-5π(7.8)sin(5π*4.4+π\3)=-106.67m/s
c.acceleration
a=d^2x/dr^2
-(5π)^2(7.8) cos (5π*t+π\3)
at t=4.4
-(5π)^2(7.8)cos(5π*4.4+π\3)=-947.3m/s^2
d. Phase =(5πrad/s)t+π\3
At t=4.4
5π×4.4+π\3=70.17 rad
e.frequency
Given x= 7.8cos(5πt+π\3
Compare with x=Acos(2πft)
2πft=5πt
F=2.5Hz
f.T=1\f
T=1/2.5=0.4sec