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2 years ago

<5and <6 are complemary angles. M<5=13. what is the meausure of <6.

2 answers:

6 0

What does the word "complementary" mean in "complementary angles?"
If angles 7 and 8 are complementary, their measures add up to ... what?

Semmy [17]2 years ago

4 0

If <5= 13 then <6=77

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21 is 42% of what number

Step2247 [10]

21 is 42% of 50 , So the correct answer is 50

4 0

2 years ago

Distribute (2m-5m)(-5)

Reika [66]

First Method (Distributive Property)

(2m - 5m) (-5)

Rearrange the equation to make it easier.

(-5) (2m - 5m)

In distributive property, it's all about multiplying. The -5 goes to the 2m and the 5m. Like this: (-5 • 2m) - (-5 • 5m).

-10m + 25m

15m

Second Method

(2m - 5m) (-5)

Since 2m and 5m have the same variable, we can subtract them.

(-3m) (-5)

Multiply.

15m

15m is your answer. I hope this helps!

6 0

2 years ago

What is the domain and range of the relation shown?

Helga [31]

Answer:

{-4 ≤ x ≤ 4}

{-4 ≤ y ≤ 4}

Step-by-step explanation:

We’ll domain is the amount of x values,

Range is the amount of y values

_______________________________

Domain:

Starts from -4 to 4

{-4 ≤ x ≤ 4}

I made the sign less than or equal to because the circle lines are solid.

Range:

This starts from -4 to 4 also.

{-4 ≤ y ≤ 4}

<em>answer choices A. is correct</em>

<em />

<em>Hope this helps :)</em>

5 0

2 years ago

Read 2 more answers

PLEASE HELP ME!!!

Dovator [93]

Stairs because they can’t possibly walk up the stairs cause then they’ll fall

8 0

2 years ago

Read 2 more answers

Axis of sym: x =

marta [7]

Answer:

<h2>SEE BELOW</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

quadratic function
PEMDAS

<h3>let's solve:</h3>

vertex:(h,k)

therefore

vertex:(-1,4)

axis of symmetry:x=h

therefore

axis of symmetry:x=-1

to find the quadratic equation we need to figure out the vertex form of quadratic equation and then simply it to standard form i.e ax²+bx+c=0

vertex form of quadratic equation:

y=a(x-h)²+k

therefore

y=a(x-(-1))²+4
y=a(x+1)²+4

it's to notice that we don't know what a is

therefore we have to figure it out

the graph crosses y-asix at (0,3) coordinates

so,

3=a(0+1)²+4

simplify parentheses:

$3 = a(1 {)}^{2} + 4$

simplify exponent:

$3 = a + 4$

therefore

$a = - 1$

our vertex form of quadratic equation is

y=-(x+1)²+4

let's simplify it to standard form

simplify square:

$y = - ( {x}^{2} + 2x + 1) + 4$

simplify parentheses:

$y = - {x}^{2} - 2x - 1 + 4$

simplify addition:

$y = - {x}^{2} - 2x + 3$

therefore our answer is D)y=-x²-2x+3

the domain of the function

$x\in \mathbb{R}$

and the range of the function is

$y\leqslant 4$

zeroes of the function:

$- {x}^{2} - 2x + 3 = 0$

$\sf divide \: both \: sides \: by \: - 1$

${x}^{2} + 2x - 3 = 0$

$\implies \: {x}^{2} + 3x - x + 3 = 0$

factor out x and -1 respectively:

$\sf \implies \: x(x + 3) - 1(x + 3 )= 0$

group:

$\implies \: (x - 1)(x + 3) = 0$

therefore

$\begin{cases} x_{1} = 1 \\ x_{2} = - 3\end{cases}$

4 0

2 years ago