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2 years ago

Which statement is most likely true about KOH?

Chemistry

2 answers:

LekaFEV [45]2 years ago

5 0

you need to include the statements

konstantin123 [22]2 years ago

3 0

Answer: Which statements

Explanation: It turns blue litmus red. or Hydrogen gas is highly flammable.

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C8H10N4O2 is the chemical formula for caffeine, there are 8 carbons. List the 3 remaining elements in caffeine and how many atom

Nataly [62]

Caffeine that is C8H10N402 is molecule which made up of 4 different elements. apart from carbon the other element includes

element symbol
nitrogen N
oxygen O
hydrogen H
The number of atom present in caffeine molecule are as follows

Nitrogen=4 atoms
Oxygen=2 atoms
Hydrogen=10 atoms

4 0

2 years ago

If an atom can form more than one cation, the cation with the lowest charge ends with which set of letters?

Verdich [7]

Answer:

Answer is A

Explanation:

Now we know that an atom wants to complete its outer shell while keeping electrons in pairs of two now in A there are four electrons which which can be ejected while in B will want to accept 3 electrons to complete its shell as ejecting five will take lot of energy similar case will be for C,D and E which would want to accept 2,1,0 electrons respectively

3 0

2 years ago

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Which of the following is not among the three likely sources of heat during the formation of the Earth?

Romashka-Z-Leto [24]

Answer:

Constant volcanic eruption

Explanation:

5 0

2 years ago

Nitrates are _____.

horrorfan [7]

Answer:

Nitrates are oxidising agents

3 0

2 years ago

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N2(g) + 3H2(g) → 2NH3(g) How many grams of N2 are required to produce 240.0g NH3?

just olya [345]

Answer:

$\large \boxed{\text{197.4 g}}$

Explanation:

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 28.01 17.03

N₂ + 3H₂ ⟶ 2NH₃

m/g: 240.0

(a) Moles of NH₃

$\text{Moles of NH}_{3} = \text{240.0 g NH}_{3}\times \dfrac{\text{1 mol NH}_{3}}{\text{17.03 g NH}_{3}}= \text{14.09 mol NH}_{3}$

(b) Moles of N₂

$\text{Moles of N$_{2}$} = \text{14.09 mol NH}_{3} \times \dfrac{\text{1 mol N$_{2}$}}{\text{2 mol NH}_{3}} = \text{7.046 mol N$_{2}$}$

(c) Mass of N₂

$\text{Mass of N$_{2}$} =\text{7.046 mol N$_{2}$} \times \dfrac{\text{28.01 g N$_{2}$}}{\text{1 mol N$_{2}$}} = \textbf{197.4 g N$_{2}$}\\\\\text{The reaction requires $\large \boxed{\textbf{197.4 g}}$ of N$_{2}$}$

7 0

2 years ago

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