i think the answer is D 10.0
The components of the net force on the cart is determined as 67.66 N.
<h3>
Component of net force on the cart</h3>
The component of net force on the cart is determined by resolving the forces into x and y -components.
T1 = 30 N
T2 = 40 N
T1x = -30cos(0) = 30 N
T1y = 30sin(0) = 0
T2x = 40 x cos(30) = 34.64 N
T2y = 40 x sin(3) = 20 N
∑X = 30 N + 34.64 N = 64.64 N
∑Y = 0 + 20 N = 20 N
<h3>Resultant force</h3>
R = √(64.64² + 20²)
R = 67.66 N
Learn more about net force here: brainly.com/question/25239010
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The technical name for super glue type adhesive is Cyanoacrylate glue
Answer:
Factor = 8.77
Explanation:
Fraction of collision with energy greater than or equal to the activation energy can be given by the formula:
R = 8.314 J/mol.K
When Temperature = 34⁰C = 34 + 273 = 307 K
When Temperature = 52⁰C = 52 + 273 = 325 K
Factor = 8.77
Given:
Water 4 m deep
Required:
Pressure at the bottom of the
tank
Solution:
p2 – p1 = gh
p2 – p1 = p = gh
p
= gh =
1000kg/m3 (9.8m/s2)(4m)
<span>p =
39200 Pa</span>