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2 years ago

Determine if "h=3" is a solution. 3h=2(h+2)-1

Mathematics

2 answers:

lutik1710 [3]2 years ago

4 0

Answer:

Yes is a solution

Step-by-step explanation:

3h = 2(h+2)-1

We replace h=3

3*3 = 2(3+2) - 1

Solve

9 = 2(5)-1

9 = 10 - 1

9 = 9

Is correct h= 3

when we manage to find the same value on both sides of equality it means that the value entered is a possible option

zhenek [66]2 years ago

4 0

Answer:

Step-by-step explanation:

3h=2(3+2)-1

3h=6h+4-1

3h=6h+3

-6h=-6h+3

-3h=3

-3h/-3=3/-3

h=-1

You might be interested in

Convert the complex number z = -12 + 5i from rectangular form to polar form.

Paha777 [63]

Answer:

$z=13(\cos 157\degree +i\sin157\degree)$

Step-by-step explanation:

The given complex number is

$z=-12+5i$

The polar form of this complex number is;

$z=r(\cos \theta +i\sin \theta)$ , where

$r=\sqrt{(-12)^2+5^2}$

$r=\sqrt{144+25}=\sqrt{169}=13$

and

$\theta =\tan^{-1}(\frac{5}{-12})$

This implies that;

$\theta=157\degree$ to the nearest degree.

Hence the polar form is

$z=13(\cos 157\degree +i\sin157\degree)$

7 0

2 years ago

5 points

jonny [76]

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

$y = \stackrel{\stackrel{m}{\downarrow }}{2}x-5\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

so we're really looking for the equation of a line whose slope is 2 and passes through (4 , -3)

$(\stackrel{x_1}{4}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{2}(x-\stackrel{x_1}{4}) \\\\\\ y+3=2x-8\implies y=2x-11$