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2 years ago

To which set of numbers does the following number belong 6.3 repeating

Mathematics

1 answer:

kenny6666 [7]2 years ago

5 0

6.3333... belongs to rational numbers.

Any number which can be represented in the form of p/q where $q\neq 0$ is known as rational number.

Any repeating number is rational.

Proof:

Let x= 6.3333.......... -(i)

Multiply both sides by 10

10 x= 63.3333........... -(ii)

Subtracting equation i from equation ii

9x= 57

x= 57/9 which is in p/q form.

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I went to the grocery store with $50. I purchased two gallons of milk for $3 each, a loaf of bread for $2, and three dozen of eg

Fofino [41]

Answer:

The answer to your question is $36

Step-by-step explanation:

Data

Total money = $50

2 gallons of milk = $3

a loaf of bread = $2

a dozen of eggs = $3

Write an equation to solve this problem

Cost of 2 gallons of milk + a loaf of bread + 3 dozens of eggs + remainder = total cost

Substitution

$3 + $2 + 3($3) + remainder = $50

Simplification

3 + 2 + 9 + remainder = 50

remainder = 50 - 3 - 2 - 9

result

remainder = $36

4 0

2 years ago

Imogene invested $8,000 in a bank account that pays 8 percent simple interest at the end of each year. Her friend invested the s

Natali5045456 [20]

The right system of equations to describe the situation would be on the form:

x1 = 8000 + y1*t

and

x2 = 8000 + y2*t

where x1 and x2 represents the total money of Imogene and her friend respectively at the end of t years.

Now for the value of amount earned, y1 and y2:

y1=8000*0.08

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2 years ago

A bag contains 5 red marbles and 4 green marbles. What is the probability of choosing a red marble then a green marble, without

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2 years ago

3^x= 3*2^x solve this equation

kompoz [17]

In the equation

$3^x = 3\cdot 2^x$

divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$

(Both answers are equivalent)

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2 years ago

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Hitman42 [59]

Answer:

Sometimes

explanation:

ive already taken this :)

8 0

3 years ago

Read 2 more answers