3(3x+4)(2x+5)
Because you factor out the 3 and then factor 6x^2+23x+20
That becomes (6x^2+8x)+(15x+20)
Factor out a two from the left and five from the right.
That makes 2x(3x+4) + 5(3x+4)
That becomes (3x+4)(2x+5)
Then put the three back in front.
Answer:
https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20
Step-by-step explanation:
so you have to write it all the way and then divide with the denominator then shift the numerator on the other side of the numerator
Answer:
8,541.023 and 154340
Step-by-step explanation:
Answer:
R(2, 4)
Step-by-step explanation:
The general equation for a circle centered at (h,k) with radius, R, is
(x-h)^2 + (y-k)^2 = R^2
Putting the values in formula,
(x-6)^2 + (y-1)^2 = 5^2
Putting the coordinates (2, 4) of the answer B(2-6)^2 + (4-1)^2 = 25
(-4)^2 + 3^2 = 25
16 + 9 = 25
25 = 25
R.H.S = L.H.S
So according to the above solution,
B) R(2, 4), is the correct answer.
Answer:
Step-by-step explanation:
Nyu thanks, I can't be helped either
