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jek_recluse [69]

2 years ago

5

Which of the following are point-slope equations of the line going through (3, 6) and (1, -2)?

1 answer:

Assoli18 [71]2 years ago

6 0

Here, first we need to calculate the slope of the line,
m = y2 - y1 / x2-x1
m = 6 + 2 / 3 -1
m = 8/ 2
m = 4

Now, Take first coordinate: y - 6 = 4 (x - 3)
Second coordinate: y + 2 = 4 (x - 1)

In short, Your Answers would be Option A & F

Hope this helps!

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A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 45.0 and 55.

yuradex [85]

Given:

Uniform distribution of length of classes between 45.0 to 55.0 minutes.

To determine the probability of selecting a class that runs between 51.5 to 51.75 minutes, find the median of the given upper and lower limit first:

45+55/2 = 50

So the highest number of instances is 50-minute class. If the probability of 50 is 0.5, then the probability of length of class between 51.5 to 51.75 minutes is near 0.5, approximately 0.45. <span />

3 0

2 years ago

Drag each tile to the correct box. not all tiles will be used.

lana66690 [7]

Answer:

$y=\frac{13}{6}x$ $y= \frac{11}{5}x$ $y = \frac{21}{9}x$ $y = \frac{19}{8}x$

Step-by-step explanation:

Given

The attached graph

Required

Equations with higher unit rate

First, calculate the unit rate of the graph

$m = \frac{y_2 - y_1}{x_2 - x_1}$

Where:

$(x_1.y_1) = (0,0)$

$(x_2.y_2) = (7,15)$

So:

$m = \frac{15 - 0}{7 - 0}$

$m = \frac{15}{7}$

$m = 2.143$

For the given options.

The unit rate is the coefficient of x

So: $y = \frac{19}{8}x$

Going by the above definition of unit rate.

$m = \frac{19}{8}$

$m = 2.375$

$y = \frac{27}{13}x$

$m = \frac{27}{13}$

$m = 2.077$

$y = \frac{21}{9}x$

$m = \frac{21}{9}$

$m = 2.333$

$y= \frac{11}{5}x$

$m= \frac{11}{5}$

$m= 2.20$

$y = \frac{15}{7}x$

$m = \frac{15}{7}$

$m = 2.143$

$y = \frac{31}{15}x$

$m = \frac{31}{15}$

$y = 2.067$

$y=\frac{13}{6}x$

$m=\frac{13}{6}$

$m=2.167$

The unit rates grater than the graph's from small to large are:

$y=\frac{13}{6}x$ $y= \frac{11}{5}x$ $y = \frac{21}{9}x$ $y = \frac{19}{8}x$

$m=\frac{13}{6}$ $m= \frac{11}{5}$ $m = \frac{21}{9}$ $m = \frac{19}{8}$

4 0

2 years ago

Read 2 more answers

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serg [7]

Answer:

e. 55 miles hope that helped

6 0

2 years ago

Read 2 more answers

A kitchen sink has a volume of 1800 cubic inches.What is the volume of a similar sink that is larger by a scale factor of 2

bonufazy [111]

Answer:

14400 cubic inches.

Step-by-step explanation:

Let l, b and h are length, breadth and height of a cuboid respectively, then

$V=l\times b\times h$

If another cuboid is larger by a scale factor of k, then kl, kb and kh are length, breadth and height of new cuboid respectively.

$V_1=kl\times kb\times kh$

$V_1=k^3(l\times b\times h)$

$V_1=k^3V$ ...(i)

It is given that a kitchen sink has a volume of 1800 cubic inches and a similar sink is larger by a scale factor of 2.

Substitute k=2 and V=1800 in equation (i).

$V_1=2^3(1800)$

$V_1=14400$

Therefore, the volume of required sink is 14400 cubic inches.

7 0

2 years ago

Pls answer! i will mark brainliest!

Volgvan

Answer:

3 inches

Step-by-step explanation:

(14+2x) × (15+2x) = 2(14×15)

210 +30x +28x + 4x² = 420

4x² + 58x - 210 = 0

2x² + 29x - 105 = 0

2x² + 35x - 6x - 105 = 0

x(2x + 35) - 3(2x + 35) = 0

(x - 3)(2x + 35) = 0

x = 3, -35/2(not possible)

3 0

2 years ago