The slope of a line perpendicular to the
graph of the equation 5x - 3y = 2 is -3/5.
<h3>How to find the slope of a line?</h3>
given that the equation is 5x - 3y = 2.
now write the equation in standard form y = mx + b
then -3y = 2 - 5x
y = -2/3 + 5x/3
y = 5/3x - 2/3
m 1*m 2 = - 1 is the formula for the slopes from a pair of perpendicular lines. where the slopes of the lines are m 1 and m 2.
Here m1 = 5/3 and m2 = -3/5.
Hence,the slope of a line perpendicular to the
graph of the equation 5x - 3y = 2 is -3/5.
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The slope of the line is “rise over run.” That’s the vertical change between the two points (the difference in the y-coordinates) divided by the horizontal change over the same segment (the difference in the x-coordinates).
Hello from MrBillDoesMath!
Answer: b = 4, h = 13
Discussion:
For a triangle with base b" and height "h, the area formula is
A= (1/2)bh.
In our case A = 26, h = 5b-7, so
26 = (1/2) b (5b-7). Multiply both sides by 2:
26*2 = b(5b-7) =>
52 = b(5b-7) =>
52 = 5b^2 - 7b => (subtract 52 from both sides)
5b^2 - 7b - 52 = 0. This factors as follows:
(b - 4) (5 b + 13) = 0 (use quadratic formula to find this)
so b = 4 and h = 5b -7 = 5*4 - 7 = 13
Thank you,
MrB
A mountain road makes the horizontal
I think it A but I’m not 100% sure
