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2 years ago

8

Derek and his friends shared two small pizzas.Derek ate 7/6 of the pizzas.Which mixed number shows how much pizza Derek ate?

2 answers:

steposvetlana [31]2 years ago

6 0

A - 1 1/6. If you divide 7 by 6, you get 1 with a remainder of 1/6.

Ostrovityanka [42]2 years ago

5 0

A. 1 1/6
7 divided by 6 6 can go into 1, 1 time so the whole number is 1 and there is 1 left over and the denominator is 6 so the answer is 1 1/6

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A stockbroker sold 70 shares of stock $14.52 each. what was the total amount of the sale?

Olenka [21]

Answer:

$1016.4 - if this is just a simple multiplication question

7 0

2 years ago

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

2 years ago

Solve for x using the given diagram

blagie [28]

Answer:

<h2>x = 1</h2>

Step-by-step explanation:

Look a t the picture.

The triangles on the picture are similar.

Therefore the sides are in proportion:

$\dfrac{8x}{10}=\dfrac{4}{5x}$ <em>cross multiply</em>

$(8x)(5x)=(4)(10)$

$40x^2=40$ <em>divide both sides by 40</em>

$x^2=1\to x=\sqrt1\\\\x=1$

7 0

2 years ago

I will give BRAINLIEST to the correct answer <br> Find the measure of angle 6.

True [87]

Answer:

m∠6 = 116°

Step-by-step explanation:

<u>first find x:</u>

7x - 17 = 2x + 78

subtract 2x from both sides: 5x - 17 = 78

add 17 to both sides: 5x = 95

divide by 5: x = 19

<u>plug x into 7x - 17</u>

7(19) - 17 = 116

∠6 and 7x - 17 are vertical angles and therefore congruent, so m∠6 also = 116°

3 0

2 years ago

Tell whether the ordered pair is a solution of the linear system. (-4,-6); -3x+y=6, -2x+y=-8

harkovskaia [24]

Plug them in... -4=x -5=y

-3x-4+-6=6 (check)
-3x-4=12-6=6 (ordered pair works with this equation)

-2x-4+-6=-8 (check)
-2x-4=8-6=2 (ordered pair does not work with this equation)

Therefore the ordered pair IS NOT the solution.

Hope this helps :)

8 0

2 years ago