Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
Answer:
1)C
2)C
Step-by-step explanation:
Fiz no Classroom!!!
Answer:
17% i think
Step-by-step explanation:
Answer:
∠ I = 39°, ∠ J = 51°, ∠ K = 90°
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°
Sum the3 angles and equate to 180
3x + 21 + 5x + 21 + 90 = 180, that is
8x + 132 = 180 ( subtract 132 from both sides )
8x = 48 ( divide both sides by 8 )
x = 6
Then
∠ I = 3x + 21 = 3(6) + 21 = 18 + 21 = 39°
∠ J = 5x + 21 = 5(6) + 21 = 30 + 21 = 51°
∠ K = 90°
A. Length: 7, Width: 5
B. Perimeter: 24
C. Area: 35
