Let x be the mass of the paperbacks and y be the mass of the textbook.
20x + 9y = 44.4 ----------- (1)
25x + 10y = 51 -------------(2)
(1) x 10:
200x + 90y = 444 --------(1a)
(2) x 9:
225x + 90y = 459 --------(2a)
(2a) - (1a):
25x = 15
x = 0.6 -------- sub into (1)
20 (0.6) + 9y = 44.4
12 + 9y = 44.4
9y = 44.4 - 12
9y = 32.4
y = 3.6
So the paperback's mass is 0.6 pounds and textbook is 3.6 pounds
The rectangle with maximum area will actually be a square.
Each side will be of length 7/4 = 1 3/4.
Answer:
A
Step-by-step explanation:
We have to determine the future value of the annuity to determine which account has a greater value
Future value = Amount x annuity factor
annuity factor = Annuity factor = {[(1+r)^n] - 1} / r
Account A = 300 x[ (1.042)^15 - 1 ] / 0.042 = $6097.14
Account B = 250 x[ (1.051)^15 - 1 ] / 0.051 = $5435,42
Account A will be greater
Answer:
-7/30
Step-by-step explanation:
So you need to make the denominators the same number so that you can just subtract the numerators.
(10) 2/3 - (3) 9/10
20/30 - 27/30
-7/30
Answer:
A,D,E,G=83 B,C,F=97
Step-by-step explanation:
