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2 years ago

6/(x+1)-5/2=6/(3x+3)

1 answer:

6 0

If you would like to calculate 6/(x+1)-5/2=6/(3x+3), you can do this using the following steps:

6/(x+1)-5/2=6/(3x+3)
6/(x+1)-5/2=6/(3(x+1)) /*(x+1)
6 - 5/2 * (x+1) = 6/3
6 - 2 = 5/2 * (x+1)
4 = 5/2 * (x+1) /*2/5
4 * 2/5 = x + 1
8/5 - 1 = x
x = 8/5 - 5/5 = 3/5

The correct result would be 3/5.

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Write a real -world word problem that can be solved using elapsed time. Include the solution.

Olegator [25]

Greg walks into a store at 6:30 a.m.
The store opens at 8:00 a.m.
How much time does Greg have until the store opens?
8:00-6:30=. 1 hour and 30 minutes

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2 years ago

What is the following product? Assume x>/=0 ^3sqrt(x^2)*^sqrtx^3

RoseWind [281]

Answer:

$x(\sqrt[12]{x^5} )$

Step-by-step explanation:

We need to remember 2 rules when doing these:

1. $\sqrt[n]{x^a} =x^{\frac{a}{n}}$

2. $x^a*x^b=x^{ab}$

Using these 2 rules, we can simplify the product (steps shown below):

$\sqrt[3]{x^2} *\sqrt[4]{x^3} \\=x^{\frac{2}{3}}*x^{\frac{3}{4}}\\=x^{\frac{2}{3}+\frac{3}{4}}\\=x^{\frac{17}{12}}\\=x^{\frac{12}{12}+\frac{5}{12}}\\=x(x^{\frac{5}{12}})\\=x(\sqrt[12]{x^5} )$

Rearranging, we see that it is the third choice.

7 0

2 years ago

What is the value of st divided by (6r) if r =5 and t =45

SVEN [57.7K]

Write "st div. by 6r" as

st
-------
6r
45s 15s 3s
If r =5 and t = 45, but s is unknown, then we get --------- = --------- = -------
6(r) 2(5) 2

8 0

2 years ago

7x=5+5x x equals what

dybincka [34]

7x=5+5x

x=5/2

It could also be 2 1/2

3 0

2 years ago

A standard letter-sized piece of paper has a length and width of 8.5 inches by 11 inches.

den301095 [7]

Answer:

Area of the resulting rectangle = 23.375 inch²

Step-by-step explanation:

After 1 fold width or length reduces to half.

Area = Length x width

So after 1 fold area will reduce to half.

So we have

$\texttt{Area after n folds =}\frac{\texttt{Initial area}}{2^{\texttt{number of folds}}}$

Initial area = 8.5 x 11 = 93.5 inch²

Here the paper were folded completely in half, length is reduced to half and width reduced to half, that is

Number of folds = 2

$\texttt{Area after 2 folds =}\frac{\texttt{Initial area}}{2^{2}}\\\\\texttt{Area after 2 folds =}\frac{93.5}{4}=23.375inch^2$

Area after 2 folds = 23.375 inch²

Area of the resulting rectangle = 23.375 inch²

8 0

2 years ago