Try this option:
1) if V(0;0) and x= -4, then common view of the required equiation is:
(y-k)²=4p(x-h), where focus is in (h-p;k), the vertex is in (h;k), the directrix is x=h+p, p<0 and y=k is simmetry axis;
2) if the V(0;0), then h=k=0 and the required equiation is:
y²=4px;
3) if the directrix equation is x=h+p, where h=0, then p= -4 (according to the condition the directrix equation is x= -4), then the required equation is:
y²= -16x
answer: y²= -16x
Answer:
y-3=7/6(x-4)
Step-by-step explanation:
the equation for point-slope form is y-y1=m(x-x1)
first let's find the slope (m)
the formula for slope is (y2-y1)/(x2-x1)
the given points: (4,3) and (-2,-4)
label the points:
x1=4
y1=3
x2=-2
y2=-4
now substitute into the equation
m=(-4-3)/(-2-4)
m=-7/-6
m=7/6
the slope is 7/6
now substitute the numbers into the equation for point-slope form
y-3=7/6(x-4)
Hope this helps :)!
I think it's 108/11.. Pretty sure of it
Let the centre be O and the line with one end point at the centre and another at the chord CD touches the chord at S .
So CS is the half of 36.7 = 18.35
Therefore,
Therefore the measurement of arc CD is 118.7 degree.
Yes i loveing it they’re nive I guess