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2 years ago

Which is the correct rate law for the overall reaction

Chemistry

1 answer:

Leviafan [203]2 years ago

4 0

Answer:

The sum of each elementary step in a reaction mechanism must yield the overall reaction equation. The rate law of the rate determining step must agree with the experimentally determined law.

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6th grade science help me if you can c:

lesya [120]

B. Troposphere, stratosphere, mesosphere, thermosphere

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2 years ago

Two atoms with the same number of protons that have gained or lost electrons are called

Katyanochek1 [597]

Answer: Anion. The resulting of losing or gaining electrons would be Anion.

3 0

2 years ago

Draw the two chair conformations of cis 1 chloro 2 methylcyclohexane

Mrrafil [7]

In chair conformations of cyclohexane, Cl group is on the first C and methyl group is on the second C. In the cis conformation both groups should be in the same orientation, either both side chains should be up and up or down and down. In this figure its up and up.
2 figures are drawn as when the chair conformation flips, the axial groups become equatorial and equatorial groups become axial. But they remain as up or down .
When A flips to B, Cl goes from axial to equatorial and CH3 goes from equatorial to axial but both remain up.

6 0

3 years ago

A solution containing CaCl2 is mixed with a solution of Li2C2O4 to form a solution that is 3.5 × 10-4 M in calcium ion and 2.33

natka813 [3]

This is an incomplete question, here is a complete question.

A solution containing CaCl₂ is mixed with a solution of Li₂C₂O₄ to form a solution that is 3.5 × 10⁻⁴ M in calcium ion and 2.33 × 10⁻⁴ M in oxalate ion. What will happen once these solutions are mixed? Ksp (CaC₂O₄) = 2.3 × 10⁻⁹

A. Nothing will happen since both calcium chloride and lithium oxalate are soluble compounds.

B. Nothing will happen Ksp > Q for all possible precipitants.

C. A precipitate will form as calcium oxalate is not soluble to any extent.

D. A precipitate will form since Q > Ksp for calcium oxalate.

Answer : The correct option is, (D) A precipitate will form since Q > Ksp for calcium oxalate.

Explanation :

Concentration of $Ca^{2+}$ = $3.5\times 10^{-4}M$

Concentration of $C_2O_4^{2-}$ = $2.33\times 10^{-4}M$

The equilibrium chemical reaction will be:

$CaC_2O_4\rightleftharpoons Ca^{2+}+C_2O_4^{2-}$

The solubility constant expression for this reaction is:

$K_{sp}=[Ca^{2+}][C_2O_4^{2-}]=2.3\times 10^{-9}$

Now we have to calculate the ionic product for calcium oxalate.

$Q_{sp}=[Ca^{2+}][C_2O_4^{2-}]$

$Q_{sp}=(3.5\times 10^{-4})\times (2.33\times 10^{-4)$

$Q_{sp}=8.2\times 10^{-8}$

From this we conclude that, $Q_{sp}>K_{sp}$ that means a white solid precipitate of calcium oxalate will be formed when the solutions are mixed.

Hence, the correct option is, (D)

4 0

2 years ago

The concentration of Pb²⁺ in a sample of wastewater is to be determined by using gravimetric analysis. To a 100.0-mL sample of t

svetoff [14.1K]

Answer:

0.005404 M

Explanation:

$Pb^{2+}(aq) + Na_{2}CO_{3}(aq) ---> PbCO_{3}(s) + 2Na^{+}(aq)$

Since you added an excess of sodium carbonate you warrantied that all the $Pb^{+2}$ in the sample reacted with it. So we can say that the insoluble lead (II) carbonate $PbCO_{3}$ contains all the $Pb^{+2}$ ions in the original sample.

The moles of $PbCO_{3}$ are:

$moles-of-PbCO_{3}=\frac{mass-of-PbCO_{3}}{Molecular-weight-of- PbCO_{3}}=\frac{0.1443g}{267\frac{g}{mol}}=0.00054 mol$

One mol of $Pb^{+2}$ is required to form one mol of $PbCO_{3}$ . So, the stoichiometric relationship between them is 1:1.

$Pb^{+2} +CO_{3}^{-2} - - - > PbCO_{3}$

Knowing this, 0.00054 is also the number of moles of $Pb^{+2}$ in the original sample.

So, the concentration of $Pb^{+2}$ in the original sample is:

$M = \frac{mol-of-Pb^{+2}}{volume-wastewater-(liters)}=\frac{0.00054}{0.1L}=0.005404 M$

8 0

2 years ago