Answer:
The answer would be at 120°C
<u>Answer:</u> The moles of hydrochloric acid is 
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
Or,
We are given:
Molarity of solution = 0.5173 M
Volume of solution = 
Putting values in above equation, we get:
Hence, the moles of hydrochloric acid is
90% of energy is lost. only 10% is left.
therefore the answer is B. 90%
Hydrogen and carbon atoms
Explanation:
Hydrocarbons are molecules that are made up of hydrogen and carbon atoms only.
They are made up of covalent bonds between the carbon and hydrogen atoms.
There is a wide range of hydrocarbons due to the unique properties of carbon.
Most of the hydrocarbons comes from crude oil, natural gas and coal.
When hydrocarbons burn, they produce water and carbon dioxide alone.
They are used as fuel in industrial processes because they produce heat energy.
learn more:
Hydrocarbons brainly.com/question/6126420
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Answer:
1.99grams
Explanation:
- First, we need to calculate the molar mass of the compound: Ca(HCO3)2
Ca = 40g/mol, H = 1g/mol, C = 12g/mol, O = 16g/mol
Hence, Ca(HCO3)2
= 40 + {1 + 12 + 16(3)}2
= 40 + {13 + 48}2
= 40 + {61}2
= 40 + 122
= 162g/mol
Molar mass of Ca(HCO3)2 = 162g/mol
- Next, we calculate the mass of oxygen in one mole of the compound, Ca(HCO3)2.
Oxygen = {16(3)}2
= 48 × 2
= 96g of Oxygen
- Next, we calculate the percentage composition of oxygen by mass by dividing the mass of oxygen in the compound by the molar mass of the compound i.e.
% composition of O = 96/162 × 100
= 0.5926 × 100
= 59.26%.
- The number of moles of the compound, Ca(HCO3)2, must be converted to mass by using the formula; mole = mass/molar mass
0.0207 = mass/162
Mass = 162 × 0.0207
Mass = 3.353grams
However, in every gram of Ca(HCO3)2, there is 0.5926 g of oxygen
Hence, in 3.353grams of Ca(HCO3)2, there will be;
0.5926 × 3.353
= 1.986
= 1.99grams.
Therefore, there is 1.99grams of Oxygen in 0.0207 moles (3.353g) of Ca(HCO3)2.
