In reaching her destination, a backpacker walks with an average velocity of 1.22 m/s, due west. This average velocity results be
cause she hikes for 6.44 km with an average velocity of 2.53 m/s, due west, turns around, and hikes with an average velocity of 0.445 m/s, due east. How far east did she walk? Can someone please help me please? I really really need help on this please!!!!
Wow! 2.95m/s is a mighty fast pace for a backpacker. Must have one of those Star Wars anti-gravity packs. Also, I would be curious as to why she passed her destination and then walked back. <span>Anyway, it goes like this: </span> <span>Say the time walking east is 't', and the total time is 'T'. </span> <span>Then 5340 m + .511 t = 1.43 T </span> <span>(This assumes that velocity is positive in both directions) </span> <span>Two unknowns in one equation. But you also know that the time spent walking west is </span> <span>5340m/ 2.95m/s = 1810 sec. </span> <span>and the total time T = 1810 +t </span> <span>Substitute this into the first equation, and you can solve for t = 3092 sec. </span> <span>Then T = 4902 sec. and distance walked east is .511t = 1580m.</span>
