Answer:
-54
Step-by-step explanation:
8a + 7b + c = 9
We want -6c, but we have c in the equation so multiply by -6
-6(8a + 7b + c) = 9*-6
-48a -42b -6c = -54
Rearranging the equation
-6c - 48a - 42b = -54
In order to begin we must start off with the formula for the area of a triangle, which is a=1/2b(h) where a is area, b is base, and h is height.
In this scenario, we know that the area is 45cm^2 and the base is 2h+12 (since it is twice it’s height plus twelve). We can plug this into the area equation and then proceed to solve out accordingly.
a=1/2b(h)
45=1/2(2h+12)(h)
90=(2h+12)(h)
90=2h^2 + 12h
0= 2h^2 + 12h - 90
Simplify by dividing the two out.
h^2 + 6h - 45 = 0.
Now plug into the quadratic formula (with a=1, b=6, and c=-45) as shown in the image below.
After plugging the equation in and solving, we come to the idea that h is roughly equal to 4.34. We can now plug this back into the triangle area formula to solve out for b.
a=1/2b(h)
45=1/2(2h + 12)(h)
45=1/2(20.69)(4.34)
45=45.
In conclusion;
The height is ≈ 4.34
The base is ≈ 8.68
Hope this helps :)
Answer:
16 quarters
30 pennies
Step-by-step explanation:
q= quarters
p=pennies
set up a system of equations. One equation is for total value, the other is total # of coins.
q + p = 46
0.25q + 0.01p = 4.30 -> multiply this equation by 4 so you can subtract from the top equation
q + P =46
1q + 0.04p = 17.20
subtract the bottom equation from the top
0.96p = 28.8
divide by 0.96
p=30
substitute p in the top equation
q + 30 = 46
subtract 30 from both sides
q = 16
<span>1. </span><span>4x –y = 8, the point (-4, 3)
Let’s say y = 0
=> 4x – 8
=> 4x / 4 = 8 /4
=> x = 2
So the point is (2 , 0).
Now, we have 2 forms, the (2,0) and the (-4, 3)
=> (y2 – y1)(x2 – x1) = m
=> m = (0 - 3)(2-(-4))
=> m = (0 - 3)(2+4)
=> m = (-3)(6)
=> m = -1/2
Thus,
y = -1/2x + a
=> 0 = -1 + a so a = 1
y = -x/2 + 1</span>
