A football field is 120 yards long (100 yards playing field plus 2 end zones 10 yards each) by 53 1/3 yards wide.
1 yard = 3 feet.
120 yards x 3 feet per yard = 360 feet
53 1/3 yards x 3 = 160 feet.
The area of the football fields is 360 x 160 = 57,600 square feet.
1 bag covers 2000 square feet:
57,600 / 2,000 = 28.8 bags, round up to 29 bags are needed.
1 bag cost $27.79.
29 bags x $27.79 = $805.91 total cost.
Answer:
The 99% confidence interval for the population mean reduction in anxiety was (1.2, 8.6).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 27 - 1 = 26
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 26 degrees of freedom(y-axis) and a confidence level of . So we have T = 2.7787.
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 4.9 - 3.7 = 1.2.
The upper end of the interval is the sample mean added to M. So it is 4.9 + 3.7 = 8.6.
The 99% confidence interval for the population mean reduction in anxiety was (1.2, 8.6).
Answer:
£375
Step-by-step explanation:
The tax changed from 17.5% of the car's price to 20% of the car's price, an increase of 2.5% of the car's price.
The increased tax amount is ...
0.025 × £15000 = £375
The price of the car went up by £375 due to the increase in VAT.
8 x - 4 (5 - x) = -44
mutiply the bracket by -4
(-4)(5) = -20
(-4)(-x)= 4x
8x-20+4x= -44
8x+4x-20= -44 ( combine like terms )
12x-20= -44
move -20 to the other side
sign changes from -20 to +20
12x-20+20= -44+20
12x= -44+20
12x= -24
divide both sides by 12
12x/12= -24/12
Answer: x= -2
Answer:
475.
Step-by-step explanation:
We have been given that for a normal distribution with μ=500 and σ=100. We are asked to find the minimum score that is necessary to be in the top 60% of the distribution.
We will use z-score formula and normal distribution table to solve our given problem.
Top 60% means greater than 40%.
Let us find z-score corresponding to normal score to 40% or 0.40.
Using normal distribution table, we got a z-score of .
Upon substituting our given values in z-score formula, we will get:
Therefore, the minimum score necessary to be in the top 60% of the distribution is 475.