Answer:
B
Step-by-step explanation:
Answer:
Length:8 m
Width:3 m
Step-by-step explanation:
<u><em>The complete question is</em></u>
If the perimeter of a rectangle is 22 meters, and the perimeter of a right triangle is 12 meters (the sides of the triangle are half the length of the rectangle, the width of the rectangle, and the hypotenuse is 5 meters). How do you solve for L and W, the dimensions of the rectangle.
step 1
<em>Perimeter of rectangle</em>
we know that
The perimeter of rectangle is equal to
we have
so
Simplify
-----> equation A
step 2
Perimeter of triangle
The perimeter of triangle is equal to
so
Multiply by 2 both sides
----> equation B
Solve the system of equations by graphing
Remember that the solution is the intersection point both graphs
using a graphing tool
The solution is the point (8,3)
see the attached figure
therefore
The dimensions of the rectangle are
Length:8 m
Width:3 m
Sin D - 4/5
This is because sin would mean Opposite/Hypotenuse, and so if the angle is D then the opposite is 4.
sin C - 3/5
This is basically the same reason as sin D, however this time the Opposite is 3.
sin D × cos D - 4/5 × 3/5 = 12/25
For here, you just get the fractions of sin D, which we got earlier, and cos D, which would be Adjacent/Hypotenuse and therefore 3/5.
tan C × tan D - Not an option
cos C × tan D - 16/15
This is because cos C would be 4/5, and tan D would be 4/3 (Opposite/Adjacent) and multiplying those fractions together gives 16/15.
I hope this helps!
Answer:
-4x + 12
Step-by-step explanation:
2(x+6)-6x
2x + 12 - 6x
combine llike terms
2x - 6x = -4x
-4x + 12
Answer:
step 4
Step-by-step explanation: