Answer:
y 6 +
Step-by-step explanation:
3x - 4y 24
-3x -3x
(-4y 24 - 3x ) / -4
y 6 +
Answer:
a) Is it possible for Fred to accomplish this? Yes
b) If it is possible, what score does he need in his next game? 293
Step-by-step explanation:
Step 1
Let us represent the number of games Fred bowled to get an average of 177 = X
His total points scored in that game would be
177 × X
= 177X
To achieve an average of 178 for his next game,
The total number of points he scored was 199, hence that is represented as:
178 = 177X + 199/ X + 1
178(X + 1) = 177X + 199
178X + 178 = 177X + 199
178X - 177X = 199 - 178
X = 21
Hence, Fred bowled 21 games to achieve an average of 178
Therefore, the score he needs to have on the 23rd game is obtained as:
= (23 × 183) - (22 × 178) = 4209 - 3916 = 293
Therefore, it is possible for Fred to raise his average from 178 to 183 in a single game, but he must bowl 293 in his next game to do this.
Answer:
96 units^2
Step-by-step explanation:
The formula for the area of a triangle: b*h/2
b= 12
h= 16
Work:
12*16/2
192/2
96 uints^2
There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
Answer:
= 5n
Step-by-step explanation:
There is a common difference d between consecutive terms
d = 10 - 5 = 15 - 10 = 20 - 15 = 25 - 20 = 30 - 25 = 5
This indicates the sequence is arithmetic with explicit formula
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 5 and d = 5 , then
= 5 + 5(n - 1) = 5 + 5n - 5 = 5n