The rule to remember about generating the perpendicular family to a line is we swap the coefficients on and x and y, remembering to negate one of them. Then the constant is set directly from the intersecting point.
So we have
y = 3x + 2
-3x + 1y = 2
Swapping and negating gets the perpendiculars; the constant is as yet undetermined.
1x + 3y = constant
Since we want to go through (0,2), we could have just written
x + 3y = 0 + 3(2) = 6
3y = -x + 6
y = (-1/3) x + 2
Third choice
1. discriminant = b^2 - 4ac = (-5)^2 - (4 x 1 x 7) = 25 - 28 = -3 [imaginary root]
2. discriminant = (-5)^2 - (4 x 1 x -4) = 25 - (-16) = 25 + 16 = 41 [real and irrational root]
3. discriminant = (8)^2 - (4 x 16 x 1) = 64 - 64 = 0 [double root]
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hope it helps