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2 years ago

12f+f simplified please and thank you

Mathematics

2 answers:

____ [38]2 years ago

6 0

Answer:

the correct answer is

f(12+1)

because 12*f=12f

and f*1 is the same f

Mice21 [21]2 years ago

6 0

Answer: 13f

Step-by-step explanation: f=1f. 12+1=13.

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What is the volume of the oblique cylinder rounded to the nearest cm^3?

SVETLANKA909090 [29]

Answer: $32009355.90cm^3$

Step-by-step explanation:

Formula: $V=Bh\\$

Since the base is a circumference, we can replace B for the area of a circumference formula.

$V=\pi r^2h$

What we have here is 12 ft as the diameter of the circumference. A diameter is twice the radius, therefore we can conclude that if we take the diameter and divide it by 2, it will give us the radius.

$12/2=6ft$ this is the radius.

Now plug all this information into your formula.

$V=(3.14)(6ft)^2(10ft)\\V=(3.14)(36ft^2)(10ft)\\V=1130.40ft^3$

Our values are in feet but the question requires cm. Let's convert from $ft^3$ to $cm^3$ .

Normally, our conversion factors are raised to the power of 1, but in this case it's raised to the power of 3. So, first let's see how many cm are 1 ft.

$1ft=30.48cm$

Here is where magic comes. We can raise both to the power of 3, in order to find the cubic ft and cm that we need as our conversion factors.

$(1ft)^3=(30.48cm)^3\\1ft^3=28316.8cm^3$

Now we have our conversion factors.

$1130.40ft^3(\frac{28316.84cm^3}{1ft^3})=32009355.90cm^3$

4 0

2 years ago

-6<br><img src="https://tex.z-dn.net/?f=%20-%206%20%2B%203%20%5Ctimes%204%20-%2011" id="TexFormula1" title=" - 6 + 3 \times 4 -

ipn [44]

The answer is -5

Explanation:

-6 + 3 x 4 -11=
-6 + 12 -11=
+ 6 -11 = -5

4 0

2 years ago

Read 2 more answers

Determine the commutators of the operators a and a+,where a = (x + ip)/2 ^1/2 and a+ = (x - ip)/ 2 ^1/2

Vsevolod [243]

Answer:

Given that:

$a = (\frac{x+ip}{2})^{\frac{1}{2}}$ and $a+= (\frac{x-ip}{2})^{\frac{1}{2}}$

if a , a+ commutator, it obeys $aa^+ = a^+a$

First find:

$aa^+ = (\frac{x+ip}{2})^{\frac{1}{2}} (\frac{x-ip}{2})^{\frac{1}{2}}$

= $(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}$

Now;

$a^+a =(\frac{x-ip}{2})^{\frac{1}{2}} (\frac{x+ip}{2})^{\frac{1}{2}} = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}$

= $(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}$

therefore, $aa^+ = a^+a$ which implies the operators a and a+ are commutators.

7 0

2 years ago

How many solutions does the equation below have?

Elina [12.6K]

Answer:

1.one solution is the answer

Step-by-step explanation:

3 0

2 years ago

Set up the trig equation with the correct values plugged in that you would use to solve for h. (You do not need to solve)

Usimov [2.4K]

From the reference of the 18 degree angle, 'h' is the opposite side and 100 is the adjacent side.

The trig ratio which uses both the opposite and adjacent sides is the tangent.

tan(18) = opp/adj = h/100

Trig equation:
tan(18) = h/100

3 0

2 years ago