Michael took the return trip at a velocity 33.75 miles per hour.
<h3>How fast did Michael drive in his return trip?</h3>
Let suppose that Michael drove in <em>straight line</em> road and at <em>constant</em> velocity. Therefore, the speed of the vehicle (v), in miles per hour, can be defined as distance traveled by the vehicle (d), in miles, divided by travel time (t), in hours.
First trip
45 = s / 3 (1)
Second trip
v = s / 4 (2)
By (1) and (2):
45 · 3 = 4 · v
v = 33.75 mi / h
Michael took the return trip at a velocity 33.75 miles per hour.
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Answer:
10
Step-by-step explanation:
We need to perform multiplication and addition property for this problem to represent the final result in decimal form. So, the expression is,
9x100+2x10+3x0.1+7x0.001 .
Now 9 x 100= 900
2 x= 10= 20
3x0.1= 0.3
7x 0.001=0.007
Now we can all the numbers. Hence,
900+20+0.3+0.007=920.307
So, the decimal number is 930.307.
The coordinates would be (-3,-1)