consider the motion along the X-direction
X = horizontal displacement = 80 m
= initial velocity along the x-direction = v Cos60
t = time of travel
using the equation
X = t
80 = (v Cos60) (t)
t = 160/v eq-1
consider the motion in vertical direction :
Y = vertical displacement = 20 m
= initial velocity in Y-direction = v Sin60
a = acceleration = - 9.8 m/s²
t = time of travel = 160/v
using the equation
Y = t + (0.5) a t²
20 = (v Sin60) (160/v) + (0.5) (- 9.8) (160/v)²
v = 32.5 m/s
Jack Kilby invented the circuit
Perimeter=26in
Area would be to multiply the units together
To solve this problem, it would be helpful to know the density of 1 block
Density is defined as the mass of the substance per volume.
From the example given,
The density of the block is (7g)/(15.625 units^3) or 0.448 g/units^3.
So, if a block is added, the new mass is 7g + 7g = 14 g
And the volume 14 g /(density) = 1 unit^3
A and D are definitely wrong because the two rocks have different masses, so it leaves us with B and C. The most logical answer to the question is
C <span>The one with greater mass takes more force to stop.
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