Assuming that there are N lanes and runners are running in the middle of each lane,
width of each lane = (1/N) [m]turning of first lane = π×(R+(1/N)×(1/2))
turning of second lane = π×(R+((1/N)×(1/2))+(1/N))
you can get the difference in turning lane simply by subtracting turning of first lane from turning of second lane.
If i worked the problem correctly, it should be π×(1/N) meter difference between each lane
9. 2/6 and in simplified form it’s 1/3
10. 10/4 simplified is 5/2
11. 8/2 simplified is 4/1
12. 7/7 which is 1
13. Has no slope
14. 4/7
Answer: 3/2
Step by step:
3/4 + 4y/3
3/4 + 4y/3 = 4y/3 + 3/4
y= 1 1/2 = 3/2