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2 years ago

The period of 3cosx/5 is..???

1 answer:

vladimir2022 [97]2 years ago

4 0

$the\ period\ of\ cosx\ is\ 2\pi\\\\the\ period\ of\ 3cosx\ is\ 2\pi\\\\the\ period\ of\ 3cos\frac{x}{5}\ is\ 5\cdot2\pi=10\pi$

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Please help me out! I keep getting the wrong answer

Tamiku [17]

The total amount of people who ordered a large is 5 + 12 + 8 = 25 people.

The amount of customers who bought a large cold drink is 5.

The probability that someone bought a large cold drink is 5 out of 25 people.

This is 5/25 which is 1/5 which is .2

Convert the decimal to a fraction by multiplying by 100 and adding a percent sign at the end.

.2 x 100 = 20%

Edit:

The probability was supposed to be if the customer ordered a cold drink based on people who ordered large.

The amount of people who ordered a large drink is 22 + 5 = 27.

The amount of people who ordered a cold large is 5.

To find the percent, divide the people who ordered cold large by the total people who ordered large.

This would be 5/27 which in decimal form is .185185

To convert to a percent, multiply by 100 and add a percent sign after it.

.185185 x 100 = 18.5185%

The question says to round to the nearest percent so your answer is:

19%

6 0

2 years ago

What is 75.65 rounded to the nearest whole number?

Nitella [24]

Answer:

Step-by-step explanation:

if the number after period is bigger than 5.. then it's about the number higher than the number befor the period

sorry if u have trouble understanding what I said I'm really not good at explaining:)

5 0

1 year ago

Read 2 more answers

Find what n equals 8(2n-2) = 4 - 4n (explanation please)

slavikrds [6]

Answer:

$\huge\boxed{n=1}$

Step-by-step explanation:

In order to find the value of n that satisfies this equation, we can perform a series of algebraic steps on it to solve for n.

$8(2n-2) = 4- 4n$
Distribute in the 8 on the left side:
$16n-16=4-4n$
Add 4n to both sides
$20n-16=4$
Add 16 to both sides
$20n = 20$
Divide both sides by 20
$n=1$

Therefore, n=1 is the value of n that satisfies this equation.

Hope this helped!

6 0

2 years ago

Read 2 more answers

What is the value of i=

vaieri [72.5K]

$\sum\limits_{t=1}^3\left(4\cdot\left(\dfrac{1}{2}\right)^{t-1}\right)=4\cdot\left(\dfrac{1}{2}\right)^{1-1}+4\cdot\left(\dfrac{1}{2}\right)^{2-1}+4\cdot\left(\dfrac{1}{2}\right)^{3-1}\\\\=4\cdot\left(\dfrac{1}{2}\right)^0+4\cdot\left(\dfrac{1}{2}\right)^1+4\cdot\left(\dfrac{1}{2}\right)^2=4\cdot1+4\cdot\dfrac{1}{2}+4\cdot\dfrac{1}{4}\\\\=4+2+1=7\\\\Answer:\ \boxed{D.\ 7}$